en subtract an Integer Z17111de Funktion
99of9 (Diskussion | Beitreche) Keine Bearbeitungszusammenfassung |
Updated the implementation list Markeerung: Manuelle Zurücksetzung |
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(11 dozwischerlehnde Vërsione fun 3 Benutzer werre net aangezeichd) | |||
Zeil 26: | Zeil 26: | ||
"Z11K1": "Z1011", |
"Z11K1": "Z1011", |
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"Z11K2": "প্রথম পূর্ণসংখ্যা" |
"Z11K2": "প্রথম পূর্ণসংখ্যা" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1827", |
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"Z11K2": "πρώτος ακέραιος αριθμός" |
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} |
} |
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] |
] |
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Zeil 47: | Zeil 52: | ||
"Z11K1": "Z1011", |
"Z11K1": "Z1011", |
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"Z11K2": "দ্বিতীয় পূর্ণসংখ্যা" |
"Z11K2": "দ্বিতীয় পূর্ণসংখ্যা" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1827", |
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"Z11K2": "δεύτερος ακέραιος αριθμός " |
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} |
} |
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] |
] |
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Zeil 57: | Zeil 67: | ||
"Z17115", |
"Z17115", |
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"Z17117", |
"Z17117", |
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"Z17118" |
"Z17118", |
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"Z17570" |
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], |
], |
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"Z8K4": [ |
"Z8K4": [ |
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Zeil 81: | Zeil 92: | ||
"Z11K1": "Z1011", |
"Z11K1": "Z1011", |
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"Z11K2": "পূর্ণসংখ্যা বিয়োগ" |
"Z11K2": "পূর্ণসংখ্যা বিয়োগ" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1827", |
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"Z11K2": "αφαίρεση ακέραιου αριθμού" |
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} |
} |
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] |
] |
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Zeil 114: | Zeil 130: | ||
"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "subtracts one integer from another to give the difference as an integer" |
"Z11K2": "subtracts one integer from another to give the difference as an integer" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1827", |
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"Z11K2": "αφαιρεί έναν ακέραιο αριθμό από τον άλλο για να δώσει τη διαφορά ως ακέραιο αριθμό" |
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} |
} |
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] |
] |
Aktuaale Vërsion fum 22. Juli 2024, 07:36 Uher
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