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en English cardinal, python Z13588
id Implementasi

Tingon Wikifunctions
Tidak ada ringkasan suntingan
ERROR: number is too large for this algorithm
Baris 11: Baris 11:
"Z1K1": "Z16",
"Z1K1": "Z16",
"Z16K1": "Z610",
"Z16K1": "Z610",
"Z16K2": "def Z13587(Z13587K1):\n # define the units and tens place\n ones = [\"\", \"one \", \"two \", \"three \", \"four \", \"five \", \"six \", \"seven \", \"eight \", \"nine \", \"ten \", \"eleven \", \"twelve \", \"thirteen \", \"fourteen \", \"fifteen \", \"sixteen \", \"seventeen \", \"eighteen \", \"nineteen \"]\n tens = [\"\", \"\", \"twenty\", \"thirty\", \"forty\", \"fifty\", \"sixty\", \"seventy\", \"eighty\", \"ninety\"]\n units = [(\"quattuordecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"tredecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"duodecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"undecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000),(\"decillion\", 1_000_000_000_000_000_000_000_000_000_000_000),(\"nonillion\", 1_000_000_000_000_000_000_000_000_000_000),(\"octillion\", 1_000_000_000_000_000_000_000_000_000),(\"septillion\", 1_000_000_000_000_000_000_000_000),(\"sextillion\", 1_000_000_000_000_000_000_000),(\"quintillion\", 1_000_000_000_000_000_000), (\"quadrillion\", 1_000_000_000_000_000), (\"trillion\", 1_000_000_000_000), (\"billion\", 1_000_000_000), (\"million\", 1_000_000), (\"thousand\", 1_000), (\"hundred\", 100), (\"\", 1)]\n\n # function to convert numbers less than 1000 to words\n def words(Z13587K1):\n if Z13587K1 == 0:\n return \"\"\n elif Z13587K1 \u003C= 19:\n return ones[Z13587K1]\n elif Z13587K1 \u003C= 99:\n tens_unit = tens[Z13587K1 // 10]\n ones_unit = ones[Z13587K1 % 10]\n return tens_unit + \"-\" + ones_unit if ones_unit else tens_unit\n else:\n return ones[Z13587K1 // 100] + \"hundred and \" + words(Z13587K1 % 100)\n\n # convert numbers to words\n if Z13587K1 == 0:\n return \"zero\"\n elif Z13587K1 \u003C 0:\n return \"negative \" + Z13587(-Z13587K1)\n else:\n result = \"\"\n for unit_name, factor in units:\n count, Z13587K1 = divmod(Z13587K1, factor)\n if count \u003E 0:\n if factor == 100:\n result = result + \" \" + ones[count] + unit_name\n elif factor == 1:\n result = result + \" and \" + words(count) + unit_name\n else:\n result = result + \" \" + words(count) + unit_name\n if (result.startswith(\" and \")): result = result[5:]\n return result.strip()"
"Z16K2": "def Z13587(Z13587K1):\n # define the units and tens place\n ones = [\"\", \"one \", \"two \", \"three \", \"four \", \"five \", \"six \", \"seven \", \"eight \", \"nine \", \"ten \", \"eleven \", \"twelve \", \"thirteen \", \"fourteen \", \"fifteen \", \"sixteen \", \"seventeen \", \"eighteen \", \"nineteen \"]\n tens = [\"\", \"\", \"twenty\", \"thirty\", \"forty\", \"fifty\", \"sixty\", \"seventy\", \"eighty\", \"ninety\"]\n units = [(\"quattuordecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"tredecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"duodecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"undecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000),(\"decillion\", 1_000_000_000_000_000_000_000_000_000_000_000),(\"nonillion\", 1_000_000_000_000_000_000_000_000_000_000),(\"octillion\", 1_000_000_000_000_000_000_000_000_000),(\"septillion\", 1_000_000_000_000_000_000_000_000),(\"sextillion\", 1_000_000_000_000_000_000_000),(\"quintillion\", 1_000_000_000_000_000_000), (\"quadrillion\", 1_000_000_000_000_000), (\"trillion\", 1_000_000_000_000), (\"billion\", 1_000_000_000), (\"million\", 1_000_000), (\"thousand\", 1_000), (\"hundred\", 100), (\"\", 1)]\n\n # function to convert numbers less than 1000 to words\n def words(Z13587K1):\n if Z13587K1 == 0:\n return \"\"\n elif Z13587K1 \u003C= 19:\n return ones[Z13587K1]\n elif Z13587K1 \u003C= 99:\n tens_unit = tens[Z13587K1 // 10]\n ones_unit = ones[Z13587K1 % 10]\n return tens_unit + \"-\" + ones_unit if ones_unit else tens_unit\n else:\n return ones[Z13587K1 // 100] + \"hundred and \" + words(Z13587K1 % 100)\n\n # convert numbers to words\n if Z13587K1 == 0:\n return \"zero\"\n elif Z13587K1 \u003C 0:\n return \"negative \" + Z13587(-Z13587K1)\n else:\n result = \"\"\n for unit_name, factor in units:\n count, Z13587K1 = divmod(Z13587K1, factor)\n if count \u003E 999:\n #ERROR: number is too large for this algorithm\n return \"ERROR: number is too large for this algorithm\"\n if count \u003E 0:\n if factor == 100:\n result = result + \" \" + ones[count] + unit_name\n elif factor == 1:\n result = result + \" and \" + words(count) + unit_name\n else:\n result = result + \" \" + words(count) + unit_name\n if (result.startswith(\" and \")): result = result[5:]\n return result.strip()"
}
}
},
},

Revisi par 6 Maret 2024 04.44

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