en English cardinal, python Z13588en Implementation
لا ملخص تعديل |
Translated content to igbo |
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(8 مراجعات متوسطة بواسطة مستخدمين اثنين آخرين غير معروضة) | |||
سطر 11: | سطر 11: | ||
"Z1K1": "Z16", |
"Z1K1": "Z16", |
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"Z16K1": "Z610", |
"Z16K1": "Z610", |
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"Z16K2": "def Z13587(Z13587K1):\n # define the units and tens place\n ones = [\"\", \"one \", \"two \", \"three \", \"four \", \"five \", \"six \", \"seven \", \"eight \", \"nine \", \"ten \", \"eleven \", \"twelve \", \"thirteen \", \"fourteen \", \"fifteen \", \"sixteen \", \"seventeen \", \"eighteen \", \"nineteen \"]\n tens = [\"\", \"\", \"twenty |
"Z16K2": "def Z13587(Z13587K1):\n # define the units and tens place\n ones = [\"\", \"one \", \"two \", \"three \", \"four \", \"five \", \"six \", \"seven \", \"eight \", \"nine \", \"ten \", \"eleven \", \"twelve \", \"thirteen \", \"fourteen \", \"fifteen \", \"sixteen \", \"seventeen \", \"eighteen \", \"nineteen \"]\n tens = [\"\", \"\", \"twenty\", \"thirty\", \"forty\", \"fifty\", \"sixty\", \"seventy\", \"eighty\", \"ninety\"]\n units = [(\"quattuordecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"tredecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"duodecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000_000),(\"undecillion\", 1_000_000_000_000_000_000_000_000_000_000_000_000),(\"decillion\", 1_000_000_000_000_000_000_000_000_000_000_000),(\"nonillion\", 1_000_000_000_000_000_000_000_000_000_000),(\"octillion\", 1_000_000_000_000_000_000_000_000_000),(\"septillion\", 1_000_000_000_000_000_000_000_000),(\"sextillion\", 1_000_000_000_000_000_000_000),(\"quintillion\", 1_000_000_000_000_000_000), (\"quadrillion\", 1_000_000_000_000_000), (\"trillion\", 1_000_000_000_000), (\"billion\", 1_000_000_000), (\"million\", 1_000_000), (\"thousand\", 1_000), (\"hundred\", 100), (\"\", 1)]\n\n # function to convert numbers less than 1000 to words\n def words(Z13587K1):\n if Z13587K1 == 0:\n return \"\"\n elif Z13587K1 \u003C= 19:\n return ones[Z13587K1]\n elif Z13587K1 \u003C= 99:\n tens_unit = tens[Z13587K1 // 10]\n ones_unit = ones[Z13587K1 % 10]\n return tens_unit + \"-\" + ones_unit if ones_unit else tens_unit\n else:\n return ones[Z13587K1 // 100] + \"hundred and \" + words(Z13587K1 % 100)\n\n # convert numbers to words\n if Z13587K1 == 0:\n return \"zero\"\n elif Z13587K1 \u003C 0:\n return \"negative \" + Z13587(-Z13587K1)\n else:\n result = \"\"\n for unit_name, factor in units:\n count, Z13587K1 = divmod(Z13587K1, factor)\n if count \u003E 999:\n #ERROR: number is too large for this algorithm\n return \"ERROR: number is too large for this algorithm\"\n if count \u003E 0:\n if factor == 100:\n result = result + \" \" + ones[count] + unit_name\n elif factor == 1:\n result = result + \" and \" + words(count) + unit_name\n else:\n result = result + \" \" + words(count) + unit_name\n if (result.startswith(\" and \")): result = result[5:]\n return result.strip()" |
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} |
} |
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}, |
}, |
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سطر 22: | سطر 22: | ||
"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "English cardinal, python" |
"Z11K2": "English cardinal, python" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "Kadịnal Bekee, Python" |
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} |
} |
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] |
] |
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سطر 34: | سطر 39: | ||
"Z1K1": "Z12", |
"Z1K1": "Z12", |
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"Z12K1": [ |
"Z12K1": [ |
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"Z11" |
"Z11", |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1002", |
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"Z11K2": "uses American names for very large numbers." |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "na-eji aha America maka ọnụọgụ buru ibu." |
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} |
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] |
] |
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} |
} |
المراجعة الحالية بتاريخ 00:09، 27 يونيه 2024
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