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en Gregorian to Bangla in javascript (Bangladesh) Z12950
zh-hans 实现

来自Wikifunctions
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无编辑摘要
 
(朆显示4位用户个13只中间版本)
第10排: 第10排:
"Z14K3": {
"Z14K3": {
"Z1K1": "Z16",
"Z1K1": "Z16",
"Z16K1": {
"Z16K1": "Z600",
"Z16K2": "function Z12926(Z12926K1, Z12926K2, Z12926K3) {\r\n const monthName = [\r\n 'Boishakh', 'Joishtho', 'Ashar', 'Shrabon',\r\n 'Bhadro', 'Ashwin', 'Kartik', 'Agrahayan',\r\n 'Poush', 'Magh', 'Falgun', 'Chaitro'\r\n ];\r\n\r\n const gYear = parseInt(Z12926K1);\r\n const gMonth = parseInt(Z12926K2)\r\n const gDay = parseInt(Z12926K3);\r\n\r\n const isLeapYear = (gYear % 4 === 0 \u0026\u0026 gYear % 100 !== 0) || (gYear % 400 === 0);\r\n\r\n let bYear;\r\n if ((gMonth === 3 \u0026\u0026 gDay \u003E= 14) || gMonth \u003E 3) {\r\n bYear = gYear - 593;\r\n } else {\r\n bYear = gYear - 594;\r\n }\r\n\r\n const bMonthArray = [\r\n [8, 9], [9, 10], [10, 11], [11, 0],\r\n [0, 1], [1, 2], [2, 3], [3, 4],\r\n [4, 5], [5, 6], [6, 7], [7, 8]\r\n ];\r\n\r\n const bDateArray = [\r\n [16, -14], [17, -13], [16, -14], [17, -13],\r\n [17, -14], [17, -14], [16, -15], [16, -15],\r\n [16, -15], [15, -16], [15, -15], [15, -15]\r\n ];\r\n\r\n let bMonth, bDate;\r\n if (gDay \u003C= 13) {\r\n bMonth = bMonthArray[gMonth][0];\r\n bDate = gDay + bDateArray[gMonth][0];\r\n } else {\r\n bMonth = bMonthArray[gMonth][1];\r\n bDate = gDay + bDateArray[gMonth][1];\r\n }\r\n\r\n if (isLeapYear \u0026\u0026 bMonth === 11 \u0026\u0026 bDate === 30) {\r\n bDate = 31;\r\n }\r\n\r\n return `${bDate} ${monthName[bMonth]} ${bYear}`;\r\n}"
"Z1K1": "Z61",
"Z61K1": "javascript"
},
"Z16K2": "function Z12926(Z12926K1, Z12926K2, Z12926K3) {\r\n const yearOffset = 593;\r\n\r\n const monthMap = [\r\n 'Boishakh', 'Joishtho', 'Ashar', 'Shrabon',\r\n 'Bhadro', 'Ashwin', 'Kartik', 'Agrahayan',\r\n 'Poush', 'Magh', 'Falgun', 'Chaitro'\r\n ];\r\n\r\n const startDates = [\r\n new Date(593, 9, 15), new Date(593, 10, 14), new Date(593, 11, 14),\r\n new Date(594, 0, 13), new Date(594, 1, 13), new Date(594, 2, 15),\r\n new Date(594, 3, 15), new Date(594, 4, 16), new Date(594, 5, 16),\r\n new Date(594, 6, 16), new Date(594, 7, 15), new Date(594, 8, 15)\r\n ];\r\n\r\n const gYear = Z12926K1;\r\n const gMonth = Z12926K2 - 1;\r\n const gDate = Z12926K3;\r\n\r\n const startDate = startDates[gMonth];\r\n let bYear = gYear - yearOffset - 1;\r\n const bMonth = monthMap[startDate.getMonth() - 1];\r\n\r\n let bDate = gDate - startDate.getDate();\r\n\r\n if (bDate \u003C 0) {\r\n const prevMonth = gMonth === 0 ? 11 : gMonth - 1;\r\n const prevStartDate = startDates[prevMonth];\r\n const daysInPrevMonth = new Date(gYear, gMonth, 0).getDate();\r\n bDate = daysInPrevMonth + bDate;\r\n\r\n if (prevMonth === 11 \u0026\u0026 gMonth === 2 \u0026\u0026 gDate \u003C 14) {\r\n bYear--;\r\n }\r\n }\r\n\r\n if (startDate.getMonth() === 0 \u0026\u0026 gMonth === 2 \u0026\u0026 gDate \u003C 14) {\r\n bYear--;\r\n }\r\n\r\n if (bDate === 0) {\r\n bDate = 30;\r\n }\r\n\r\n return `${bDate} ${bMonth} ${bYear}`;\r\n}\r\n"
}
}
},
},
第24排: 第21排:
"Z1K1": "Z11",
"Z1K1": "Z11",
"Z11K1": "Z1002",
"Z11K1": "Z1002",
"Z11K2": "Gregorian to Bangla, javascipt"
"Z11K2": "Gregorian to Bangla in javascript (Bangladesh)"
},
{
"Z1K1": "Z11",
"Z11K1": "Z1014",
"Z11K2": "Gregorian ka Bangla, javascipt"
}
}
]
]

2024年8月5号 (一) 14:37个最新修订版

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