en are strings anagrams Z10423zh-hans 函数
0xDeadbeef（讨论 | 贡献） 无编辑摘要 |
#IgboWikiFunctionsTranslation |
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"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "first string" |
"Z11K2": "first string" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1157", |
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"Z11K2": "eerste tekenreeks" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1430", |
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"Z11K2": "erste Zeichenkette" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "eriri mbụ: Eriri " |
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} |
} |
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] |
] |
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| 第37行： | 第52行： | ||
"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "second string" |
"Z11K2": "second string" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1157", |
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"Z11K2": "tweede tekenreeks" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1430", |
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"Z11K2": "zweite Zeichenkette" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "eriri nke abụọ: Eriri " |
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} |
} |
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] |
] |
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| 第51行： | 第81行： | ||
], |
], |
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"Z8K4": [ |
"Z8K4": [ |
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"Z14" |
"Z14", |
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"Z10439" |
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], |
], |
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"Z8K5": "Z10423" |
"Z8K5": "Z10423" |
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| 第63行： | 第94行： | ||
"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "are strings anagrams" |
"Z11K2": "are strings anagrams" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1157", |
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"Z11K2": "is anagram" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1430", |
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"Z11K2": "sind Zeichenketten-Anagramme" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "bụ eriri anagrams" |
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} |
} |
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] |
] |
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| 第80行： | 第126行： | ||
"Z11K1": "Z1002", |
"Z11K1": "Z1002", |
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"Z11K2": "Whether one of the input strings can have its codepoints rearranged to become the other string." |
"Z11K2": "Whether one of the input strings can have its codepoints rearranged to become the other string." |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1157", |
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"Z11K2": "of codepunten van invoertekenreeks herschikt andere tekenreeks kan worden (hoofdlettergevoelig)" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1430", |
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"Z11K2": "prüft, ob die Codepunkte der Eingabe-Zeichenkette so umsortiert werden können, dass sie die andere Zeichenkette ergeben" |
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}, |
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{ |
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"Z1K1": "Z11", |
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"Z11K1": "Z1014", |
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"Z11K2": "Ma otu n'ime eriri ntinye enwere ike ịhazigharị koodu koodu ya ka ọ bụrụ eriri nke ọzọ" |
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} |
} |
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] |
] |
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伫2024 nièng 4 nguŏk 24 hô̤ (三) 17:08兮最新版本
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